Armstrong number program in c++

An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself.

Example of Armstrong number:

Formula:- n! = n ^x (n - 1) ^x (n - 2) ^x .... ^x 1

    7 = 7^1
    371 = 3^3 + 7^3 + 1^3(27+343+1)
    8208 = 8^4 + 2^4 +0^4 + 8^4 (4096 + 16 + 0 + 4096)

How program will work?

• First initialize five integer variable like (n, a, num, temp, sum).
• Assign the default value to sum variable like sum=0.
• Now perform multiplication operation with arithmetic operator (*).
• Finally show the result on output screen.

Program of armstrong number in c++.

	#include<iostream.h>
	#include<conio.h>
		
	//ARMSTRONG NUMBERS PROGRAM
	void main()
	{
		int n, a, num, temp, sum=0;
		clrscr();

		cout<<"ENTER A NUMBER:- ";
		cin>>n;
		num = n;

		do
		{
			temp = n%10;
			a = temp*temp*temp;
			sum = sum + a;
			n = n/10;
		}
		while(n!=0);
		if(sum == num)
		{
			cout<<num<<" IS ARMSTRONG NUMBER.";
		}
		else
		{
			cout<<num<<" NOT A ARMSTRONG NUMBER.";
		}
		
		getch();
	}
	

Output:

    ENTER A NUMBER:- 371
    371 IS ARMSTRONG NUMBER.